WUT_Computer_Science/NotProgramming/ENUME/projectC/sections/16-backsubstitution-m.tex
Krzysztof kuhy Rudnicki ffa5dad02a Split 19 over-cap LaTeX reports, proving each PDF is unchanged
The 250-line cap applies to prose too, and the reports were the worst
offenders -- ENUME's projectA.tex alone was 1,876 lines. Each is now a
preamble plus one \input{} per section, which is how a long LaTeX document is
normally organised; not one byte of prose was rewritten.

"The PDF is unchanged" is checked by a script rather than by eye, because
hashing the PDF cannot work: pdflatex stamps a /CreationDate and an /ID into
every build, so two runs of the SAME source already differ. tex_fingerprint.sh
compares what a reader sees instead -- page count plus a hash of the extracted
text -- and it is stable across rebuilds of untouched sources, which is the
property that makes it usable as a gate.

It earned its keep immediately. Both ECOTE reports quote an example LaTeX
document inside an lstlisting block, so \end{document} appears in the middle
of the file; splitting on the FIRST one stranded everything after it. Same
page count, different text, caught automatically. EOPSY lab3 exposed a second
bug: a \section{} title that runs onto the next line.

Result: 19 .tex over the cap -> 1. The survivor,
ELAC/.../03-building-nfa-...tex, is 418 lines of consecutive tikz figures
with no subsection to split on and needs a hand-placed boundary.

Verified: 29 splits across two passes (section, then subsection for the
pieces still over), every one reporting `unchanged` from
scripts/tex_fingerprint.sh --check.

Co-Authored-By: Claude Opus 5 (1M context) <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_0172dj34FDpao6wsix8ZuCzE
2026-08-28 19:47:12 +02:00

39 lines
1.0 KiB
TeX

\section{backSubstitution.m}
\subsection{backSubstitution}
\begin{simplechar}
\begin{lstlisting}
function solution = backSubstitution(Matrix)
Columns = size(Matrix, 1);
Matrix = backSubstitutionOuterLoop(Matrix, Columns);
% rightmost column of the Matrix is now our result
solution = Matrix(:, size(Matrix, 2));
end
\end{lstlisting}
\end{simplechar}
\subsection{backSubstitutionOuterLoop}
\begin{simplechar}
\begin{lstlisting}
function Matrix = backSubstitutionOuterLoop(Matrix, Columns)
for k = Columns : -1 : 1
% Diagonal coefficients of matrix need to be equal to 1
Matrix(k, :) = Matrix(k, :) / Matrix(k, k);
Matrix = eliminateFactors(Matrix, k);
end
end
\end{lstlisting}
\end{simplechar}
\subsection{eliminateFactors}
\begin{simplechar}
\begin{lstlisting}
function Matrix = eliminateFactors(Matrix, k)
for row = (k - 1) : -1 : 1
Matrix(row, :) = Matrix(row, :) - Matrix(k, :) * (Matrix(row, k) / Matrix(k, k));
end
end
\end{lstlisting}
\end{simplechar}